'''
   Given an integer a and an integer b, return the smallest integer n such that if a is tripled n times and b is doubled n times, a exceeds b.

Example 1
Input:
a = 17; b = 100
Output:
5
''' 
    
    
class Solution:   
    def solve(self, a:int, b:int) -> int:
        print(f"a: {a}, b: {b}")
        triple = a
        double = b
        n = 0
        while triple < double:
            n += 1
            triple *= 3
            double *= 2
        return n

s = Solution()
print(s.solve(17, 100))
print(s.solve(4, 16806))